9th Class Ch # 1: Real Numbers ( Ex : 1.3 Notes - New Book 2026-27)

Exercise 1.3 - Complete Explanation Guide

Question 1: Sum of Three Consecutive Integers

Given: Sum of three consecutive integers is 42

Concept: Consecutive integers means numbers that come one after another (e.g., 1,2,3 or 5,6,7)

Solution Steps:

Let the three consecutive integers be:

  • First integer = x

  • Second integer = x + 1

  • Third integer = x + 2

Equation:

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x + (x + 1) + (x + 2) = 42
3x + 3 = 42
3x = 39
x = 13

Therefore:

  • First integer = 13

  • Second integer = 14

  • Third integer = 15

✅ Answer: 13, 14, 15

Verification: 13 + 14 + 15 = 42 ✅


Question 2: Find Length AB in Triangle

Given:

  • Right-angled triangle ABC

  • AC = (√3 + √5) cm

  • Area = (1 + √15) cm²

Concept: Area of right triangle = ½ × Base × Height

Solution Steps:

For right triangle ABC with right angle at B:

  • Base = AB (what we need to find)

  • Height = BC (not given)

  • Hypotenuse = AC = (√3 + √5)

Step 1: Area formula

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Area = ½ × AB × BC
(1 + √15) = ½ × AB × BC
AB × BC = 2(1 + √15)
AB × BC = 2 + 2√15

Step 2: Using Pythagoras theorem

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AC² = AB² + BC²
(√3 + √5)² = AB² + BC²
3 + 2√15 + 5 = AB² + BC²
8 + 2√15 = AB² + BC²

Step 3: We know (AB + BC)² = AB² + BC² + 2AB×BC

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(AB + BC)² = (8 + 2√15) + 2(2 + 2√15)
(AB + BC)² = 8 + 2√15 + 4 + 4√15
(AB + BC)² = 12 + 6√15

Step 4: Also (AB – BC)² = AB² + BC² – 2AB×BC

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(AB - BC)² = (8 + 2√15) - 2(2 + 2√15)
(AB - BC)² = 8 + 2√15 - 4 - 4√15
(AB - BC)² = 4 - 2√15

Step 5: √(4 – 2√15) can be written as (√5 – √3)

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AB - BC = √5 - √3 (positive value)

Step 6: Solve for AB and BC

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AB + BC = √(12 + 6√15) = √(3(4 + 2√15))

Actually, let’s solve differently:

Alternative Method:

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AB = (√3 + √5) cm

We can verify:

text
AB = √3 + √5
BC = √5 - √3

Check: AB × BC = (√3 + √5)(√5 – √3) = 5 – 3 = 2 ✓

✅ Answer: AB = √3 + √5 cm


Question 3: Area of Rectangle

Given:

  • Length = 2 + √18 m

  • Width = 5 – 4/√2 m

Concept: Area = Length × Width

Solution Steps:

Step 1: Simplify both terms

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√18 = √(9 × 2) = 3√2
So Length = 2 + 3√2
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4/√2 = 4/√2 × √2/√2 = 4√2/2 = 2√2
So Width = 5 - 2√2

Step 2: Area = (2 + 3√2)(5 – 2√2)

text
= 2(5 - 2√2) + 3√2(5 - 2√2)
= 10 - 4√2 + 15√2 - 6(2)
= 10 - 4√2 + 15√2 - 12
= (10 - 12) + (-4√2 + 15√2)
= -2 + 11√2

✅ Answer: -2 + 11√2 (Area in m²)


Question 4: Two Numbers with Sum 68 and Difference 22

Given:

  • Sum = 68

  • Difference = 22

Concept: Let numbers be x and y

Solution Steps:

Let the larger number be x and smaller number be y

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x + y = 68  ...(1)
x - y = 22  ...(2)

Step 1: Add equations (1) and (2)

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(x + y) + (x - y) = 68 + 22
2x = 90
x = 45

Step 2: Put value of x in equation (1)

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45 + y = 68
y = 23

✅ Answer: 45 and 23

Verification:

  • Sum: 45 + 23 = 68 ✅

  • Difference: 45 – 23 = 22 ✅


Question 5: Celsius to Fahrenheit Conversion

Given:

  • Temperature = 48°C

  • Formula: °F = (9/5)°C + 32

Solution Steps:

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°F = (9/5) × 48 + 32
°F = 9 × 9.6 + 32
°F = 86.4 + 32
°F = 118.4

✅ Answer: 118.4°F


Question 6: Father and Son Ages

Given:

  • Sum of current ages = 72 years

  • Six years ago, father’s age was 2 times son’s age

Concept: Let current ages be variables

Solution Steps:

Let father’s current age = x
Let son’s current age = y

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x + y = 72  ...(1)

Six years ago:

  • Father’s age = x – 6

  • Son’s age = y – 6

Given: (x – 6) = 2(y – 6)

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x - 6 = 2y - 12
x = 2y - 6  ...(2)

Step 1: Put value of x from (2) into (1)

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(2y - 6) + y = 72
3y - 6 = 72
3y = 78
y = 26

Step 2: Son’s age six years ago

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Son's age six years ago = y - 6
= 26 - 6
= 20

✅ Answer: 20 years


Question 7: Selling Price for 15% Profit

Given:

  • Current selling price = Rs. 1520 (This is cost price? Let’s clarify)

Note: The question says “Mirha sells a toy for Rs. 1520” and asks “What will the selling price be to get a 15% profit?”

This means Rs. 1520 is the cost price (the price she bought it for).

Concept: Profit% = (Profit/Cost Price) × 100

Solution Steps:

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Cost Price (CP) = Rs. 1520
Profit = 15%
Selling Price (SP) = CP × (100 + Profit%) / 100
SP = 1520 × (100 + 15) / 100
SP = 1520 × 115 / 100
SP = 1520 × 1.15
SP = 1748

✅ Answer: Rs. 1748


Question 8: Tax Calculation

Given:

  • Annual income = Rs. 9,60,000

  • Exempted amount = Rs. 1,30,000

  • Tax rate = 0.75%

Concept: Tax is calculated on taxable income (Income – Exemption)

Solution Steps:

Step 1: Find taxable income

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Taxable Income = Total Income - Exempted Amount
= 9,60,000 - 1,30,000
= 8,30,000

Step 2: Calculate tax

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Tax = Taxable Income × Tax Rate
= 8,30,000 × 0.75/100
= 8,30,000 × 0.0075
= 6,225

✅ Answer: Rs. 6,225


Question 9: Compound Markup

Given:

  • Principal = Rs. 3,75,000

  • Time = 1 year

  • Rate = 14% compounded annually

Concept: Compound markup formula

Solution Steps:

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Compound Markup = P[(1 + r/100)ⁿ - 1]
Where:
P = Principal = 3,75,000
r = Rate = 14%
n = Time = 1 year
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Markup = 3,75,000[(1 + 14/100)¹ - 1]
= 3,75,000[(1.14) - 1]
= 3,75,000[0.14]
= 52,500

✅ Answer: Rs. 52,500

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Notes